Therefore, we find that the capacitance of the capacitor with a dielectric is C = Q0 V = Q0 V0 / κ = κQ0 V0 = κC0. This equation tells us that the capacitance C0 of an empty (vacuum) capacitor can be increased by a factor of κ when we insert a dielectric material to completely fill the space between its plates.
There is another benefit to using a dielectric in a capacitor. Depending on the material used, the capacitance is greater than that given by the equation by a factor , called the dielectric constant. A parallel plate capacitor with a dielectric between its plates has a capacitance given by
When a dielectric is inserted into an isolated and charged capacitor, the stored energy decreases to 33% of its original value. (a) What is the dielectric constant? (b) How does the capacitance change?
In conclusion, understanding capacitance and dielectrics is essential for anyone exploring the principles of electrical and electronic systems. Capacitance, as a measure of a system’s ability to store energy, plays a pivotal role in powering modern devices.
Each dielectric material has its specific dielectric constant. The energy stored in an empty isolated capacitor is decreased by a factor of κ κ when the space between its plates is completely filled with a dielectric with dielectric constant κ κ.
A parallel-plate capacitor of area A and spacing d is filled with three dielectrics as shown in Figure 5.12.2. Each occupies 1/3 of the volume. What is the capacitance of this system? [Hint: Consider an equivalent system to be three parallel capacitors, and justify this assumption.]
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