So you cannot use 3.7V and 3.6V batteries even if you use two 3.7V batteries (3.7×2=7.4V) or four 1.2V batteries (1.2×4=4.8V). Hence you need a small DC-to-DC converter to get 5V, 6V or both of these, depending on the intended application.
You would need different parts for each voltage as AFAIK you can’t modify and svg value from the parts properties (the chip label field however may allow this if you replace the 3.7V label with the id label and set the value in the chip label property.) Peter Well done! 3.7 is the nominal voltage. I would not worry in changing it.
3.7 is the nominal voltage. I would not worry in changing it. When you use a battery you know that it will be above the nominal voltage when fully charged and below it when it’s empty. This happens too with a physical battery. 3.7 is the nominal voltage. Not for a 2 cell 8.2V battery which is what he is trying to make.
This toy just sits on the desk, so it’s a good candidate to modify to accept a DC power supply instead of batteries. This idea is not well suited to something like an R.C. Car, but in a pinch, you can use it on the remote control for your TV. Wall outlet power is generally alternating current, or ‘AC’.
3.7V to 5V, 5.3V, and 6V Converter Circuit: The preferred voltage levels while working in most electronics projects lie between the value 5V to 6V. However, 3.6V-3.7V batteries are found abundantly in the market with a cheap price tag.
Fig. 1 shows circuit of the 3.7V to 5V-6V DC to DC converter. It is built around switching regulator MC34063A (IC1), two 1N5819 Schottky diodes (D1 and D4), two 1N4007 rectifier diodes (D2 and D3), two 5mm LEDs (LED1 and LED2) and a few other components. Input DC voltage of 3.7V is applied to connector CON1.
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